7 Descriptive Statistics
7.1 Computing the Percentages of Students With achievementLevels
The achievementLevels function computes the percentages of students’ achievement levels or benchmarks defined by an assessment, including NAEP, TIMSS, and PISA. Take NAEP as an example: Each NAEP dataset’s unique set of cut points for achievement levels (defined as Basic, Proficient, and Advanced) is in EdSurvey. Analysts can access these cut points using the showCutPoints function:
showCutPoints(data = sdf)
#> Achievement Levels:
#> Mathematics: 262, 299, 333The achievementLevels function applies the appropriate weights and variance estimation method for each edsurvey.data.frame, with several arguments for customizing the aggregation and output of the analysis results. Namely, by using these optional arguments, users can choose to generate the percentage of students performing at each achievement level (discrete) and at or above each achievement level (cumulative), calculate the percentage distribution of students by achievement levels (discrete or cumulative) and selected characteristics (specified in aggregateBy), and compute the percentage distribution of students by selected characteristics within a specific achievement level.
The achievementLevels function can produce statistics at both the discrete and cumulative achievement levels. By default, the achievementLevels function produces results only by discrete achievement levels; when setting the returnCumulative argument to TRUE, the function generates results by both discrete and cumulative achievement levels.
To compute overall results by achievement levels, use an NCES dataset’s default plausible values in the achievementVars argument; using NAEP, for example, they are the five or 20 plausible values for the subject composite scale.
aLev0 <- achievementLevels(achievementVars = c("composite"),
data = sdf, returnCumulative = TRUE)
aLev0$discrete
#> composite_Level N wtdN Percent StandardError
#> 1 Below Basic 5731.2 5779.5052 34.132690 0.9744207
#> 2 At Basic 6695.6 6580.2181 38.861552 0.7115633
#> 3 At Proficient 3666.0 3694.7565 21.820549 0.6342187
#> 4 At Advanced 822.2 877.9837 5.185209 0.4007991In the next example, the plausible values for composite and the variable dsex are used to calculate the achievement levels, which are aggregated by the variable dsex using aggregateBy.
aLev1 <- achievementLevels(achievementVars = c("composite", "dsex"), aggregateBy = "dsex",
data = sdf, returnCumulative = TRUE)
aLev1$discrete
#> composite_Level dsex N wtdN Percent
#> 1 Below Basic Male 2880.8 2865.6455 33.666050
#> 2 At Basic Male 3266.2 3236.4034 38.021772
#> 3 At Proficient Male 1877.2 1910.7861 22.448213
#> 4 At Advanced Male 461.8 499.1392 5.863965
#> 5 Below Basic Female 2850.4 2913.8597 34.604399
#> 6 At Basic Female 3429.4 3343.8146 39.710456
#> 7 At Proficient Female 1788.8 1783.9704 21.186066
#> 8 At Advanced Female 360.4 378.8444 4.499079
#> StandardError
#> 1 1.0951825
#> 2 0.9537470
#> 3 0.7257305
#> 4 0.5081607
#> 5 1.1154848
#> 6 0.8650729
#> 7 0.8148916
#> 8 0.3888590Each level of the dsex variable aggregates to 100 for the results by discrete achievement levels. The object aLev1 created in this call to achievementLevels is a list with two data.frames: one for the discrete results and the other for the cumulative results. In the previously described code, aLev1$discrete shows only the discrete levels. To show the cumulative results, change the specified data.frame. For example,
aLev1$cumulative
#> composite_Level dsex N wtdN Percent
#> 1 Below Basic Male 2880.8 2865.6455 33.666050
#> 2 At or Above Basic Male 5605.2 5646.3287 66.333950
#> 3 At or Above Proficient Male 2339.0 2409.9253 28.312178
#> 4 At Advanced Male 461.8 499.1392 5.863965
#> 5 Below Basic Female 2850.4 2913.8597 34.604399
#> 6 At or Above Basic Female 5578.6 5506.6295 65.395601
#> 7 At or Above Proficient Female 2149.2 2162.8149 25.685145
#> 8 At Advanced Female 360.4 378.8444 4.499079
#> StandardError
#> 1 1.0951825
#> 2 1.0951825
#> 3 0.8635866
#> 4 0.5081607
#> 5 1.1154848
#> 6 1.1154848
#> 7 1.0073379
#> 8 0.3888590The aggregateBy argument sums the percentage of students by discrete achievement level up to 100 at the most disaggregated level specified by the analytical variables and determines the order of aggregation. For example, when using dsex and iep for analysis, aggregateBy = c("dsex", "iep") and aggregateBy = c("iep", "dsex") produce the same percentage but arrange the results in different ways depending on the order in the argument. When using aggregateBy = c("iep", "dsex"), the percentages add up to 100 within each category of dsex for each category of iep, respectively:
achievementLevels(achievementVars = c("composite", "dsex", "iep"),
aggregateBy = c("iep", "dsex"), data = sdf)
#>
#> AchievementVars: composite, dsex, iep
#> aggregateBy: iep, dsex
#>
#> Achievement Level Cutpoints:
#> 262 299 333
#>
#> Plausible values: 5
#> jrrIMax: 1
#> Weight variable: 'origwt'
#> Variance method: jackknife
#> JK replicates: 62
#> full data n: 17606
#> n used: 16907
#>
#>
#> Discrete
#> composite_Level dsex iep N wtdN Percent
#> Below Basic Male Yes 810.2 753.47862 66.4635116
#> At Basic Male Yes 281.6 282.52828 24.9215056
#> At Proficient Male Yes 72.8 85.69544 7.5590995
#> At Advanced Male Yes 9.4 11.97026 1.0558833
#> Below Basic Female Yes 471.2 465.33346 76.4954517
#> At Basic Female Yes 108.8 106.71734 17.5430994
#> At Proficient Female Yes 31.2 34.36986 5.6500084
#> At Advanced Female Yes 2.8 1.89454 0.3114405
#> Below Basic Male No 2067.6 2111.69806 28.6261355
#> At Basic Male No 2982.6 2952.86086 40.0289211
#> At Proficient Male No 1804.4 1825.09062 24.7408909
#> At Advanced Male No 452.4 487.16896 6.6040524
#> Below Basic Female No 2379.0 2448.49754 31.3451478
#> At Basic Female No 3318.8 3236.55190 41.4336531
#> At Proficient Female No 1757.4 1749.56228 22.3975264
#> At Advanced Female No 356.8 376.79678 4.8236727
#> StandardError
#> 2.0061208
#> 2.0783210
#> 1.4614600
#> 0.7673700
#> 2.9245271
#> 2.0864253
#> 1.6430596
#> 0.2601418
#> 1.0630715
#> 1.0125447
#> 0.7840337
#> 0.5558956
#> 1.2051321
#> 0.9207178
#> 0.8954779
#> 0.4233201Each unique value pair of the two variables (i.e., Yes + Male or No + Female) sums to 100 because of aggregateBy.
NOTE: It is not appropriate to aggregate the results by only one variable when more than one variable is used in the analysis. The same variables used in the analysis also need to be used in the argument aggregateBy(), but their order can be changed to obtain the desired results.
The achievementLevels function also can compute the percentage of students by selected characteristics within a specific achievement level. The object aLev2 presents the percentage of students by sex within each achievement level (i.e., within each discrete and cumulative level).
aLev2 <- achievementLevels(achievementVars = c("composite", "dsex"),
aggregateBy = "composite",
data = sdf, returnCumulative = TRUE)
aLev2$discrete
#> composite_Level dsex N wtdN Percent
#> 1 Below Basic Male 2880.8 2865.6455 49.58289
#> 2 At Basic Male 3266.2 3236.4034 49.18383
#> 3 At Proficient Male 1877.2 1910.7861 51.71616
#> 4 At Advanced Male 461.8 499.1392 56.85063
#> 5 Below Basic Female 2850.4 2913.8597 50.41711
#> 6 At Basic Female 3429.4 3343.8146 50.81617
#> 7 At Proficient Female 1788.8 1783.9704 48.28384
#> 8 At Advanced Female 360.4 378.8444 43.14937
#> StandardError
#> 1 0.9486797
#> 2 0.8020508
#> 3 1.1913055
#> 4 2.0076502
#> 5 0.9486797
#> 6 0.8020508
#> 7 1.1913055
#> 8 2.0076502
aLev2$cumulative
#> composite_Level dsex N wtdN Percent
#> 1 Below Basic Male 2880.8 2865.6455 49.58289
#> 2 At or Above Basic Male 5605.2 5646.3287 50.62629
#> 3 At or Above Proficient Male 2339.0 2409.9253 52.70200
#> 4 At Advanced Male 461.8 499.1392 56.85063
#> 5 Below Basic Female 2850.4 2913.8597 50.41711
#> 6 At or Above Basic Female 5578.6 5506.6295 49.37371
#> 7 At or Above Proficient Female 2149.2 2162.8149 47.29800
#> 8 At Advanced Female 360.4 378.8444 43.14937
#> StandardError
#> 1 0.9486797
#> 2 0.6131937
#> 3 1.0576369
#> 4 2.0076502
#> 5 0.9486797
#> 6 0.6131937
#> 7 1.0576369
#> 8 2.0076502The percentage of students within a specific achievement level can be aggregated by one or more variables. For example, the percentage of students classified as English learners (lep) is aggregated by dsex within each achievement level:
aLev3 <- achievementLevels(achievementVars = c("composite", "dsex", "lep"),
aggregateBy = c("dsex", "composite"),
data = sdf, returnCumulative = TRUE)
aLev3$discrete
#> composite_Level dsex lep N wtdN Percent
#> 1 Below Basic Male Yes 355.8 436.03778 15.2177175
#> 2 At Basic Male Yes 138.4 156.75146 4.8455620
#> 3 At Proficient Male Yes 27.6 31.75786 1.6620312
#> 4 At Advanced Male Yes 1.2 0.75590 0.1514407
#> 5 Below Basic Female Yes 334.2 422.06640 14.4853587
#> 6 At Basic Female Yes 96.4 102.80364 3.0744683
#> 7 At Proficient Female Yes 19.2 22.69640 1.2722408
#> 8 At Advanced Female Yes 1.2 1.80846 0.4773622
#> 9 Below Basic Male No 2523.8 2429.29192 84.7822825
#> 10 At Basic Male No 3125.0 3078.19756 95.1544380
#> 11 At Proficient Male No 1849.6 1879.02820 98.3379688
#> 12 At Advanced Male No 460.6 498.38332 99.8485593
#> 13 Below Basic Female No 2515.4 2491.67850 85.5146413
#> 14 At Basic Female No 3332.8 3240.98230 96.9255317
#> 15 At Proficient Female No 1769.6 1761.27402 98.7277592
#> 16 At Advanced Female No 359.2 377.03598 99.5226378
#> StandardError
#> 1 1.6567088
#> 2 0.7683424
#> 3 0.5680079
#> 4 0.1976280
#> 5 1.6957678
#> 6 0.7676397
#> 7 0.4289833
#> 8 0.7919682
#> 9 1.6567088
#> 10 0.7683424
#> 11 0.5680079
#> 12 0.1976280
#> 13 1.6957678
#> 14 0.7676397
#> 15 0.4289833
#> 16 0.7919682
aLev3$cumulative
#> composite_Level dsex lep N wtdN
#> 1 Below Basic Male Yes 355.8 436.03778
#> 2 At or Above Basic Male Yes 167.2 189.26522
#> 3 At or Above Proficient Male Yes 28.8 32.51376
#> 4 At Advanced Male Yes 1.2 0.75590
#> 5 Below Basic Female Yes 334.2 422.06640
#> 6 At or Above Basic Female Yes 116.8 127.30850
#> 7 At or Above Proficient Female Yes 20.4 24.50486
#> 8 At Advanced Female Yes 1.2 1.80846
#> 9 Below Basic Male No 2523.8 2429.29192
#> 10 At or Above Basic Male No 5435.2 5455.60908
#> 11 At or Above Proficient Male No 2310.2 2377.41152
#> 12 At Advanced Male No 460.6 498.38332
#> 13 Below Basic Female No 2515.4 2491.67850
#> 14 At or Above Basic Female No 5461.6 5379.29230
#> 15 At or Above Proficient Female No 2128.8 2138.31000
#> 16 At Advanced Female No 359.2 377.03598
#> Percent StandardError
#> 1 15.2177175 1.6567088
#> 2 3.3528686 0.5358274
#> 3 1.3491605 0.4574292
#> 4 0.1514407 0.1976280
#> 5 14.4853587 1.6957678
#> 6 2.3119254 0.5208317
#> 7 1.1330078 0.4270291
#> 8 0.4773622 0.7919682
#> 9 84.7822825 1.6567088
#> 10 96.6471314 0.5358274
#> 11 98.6508395 0.4574292
#> 12 99.8485593 0.1976280
#> 13 85.5146413 1.6957678
#> 14 97.6880746 0.5208317
#> 15 98.8669922 0.4270291
#> 16 99.5226378 0.7919682Users can set unique cut points that override the standard values in the achievementLevels function by using the cut points argument. In the example that follows, aLev4 uses customized cut points of 267, 299, and 333. The object aLev1 uses the standard cut points of c(262, 299, 333). The values for Proficient and Advanced are unchanged across both objects, whereas the higher threshold to reach the Basic category in aLev4 resulted in a higher percentage of male and female students being categorized as Below Basic.
aLev4 <- achievementLevels(achievementVars = c("composite", "dsex"),
aggregateBy = "dsex",
data = sdf,
cutpoints = c("Customized Basic" = 267,
"Customized Proficient" = 299,
"Customized Advanced" = 333),
returnCumulative = TRUE)
aLev4$discrete
#> composite_Level dsex N wtdN
#> 1 Below Customized Basic Male 3285.0 3262.6418
#> 2 At Customized Basic Male 2862.0 2839.4071
#> 3 At Customized Proficient Male 1877.2 1910.7861
#> 4 At Customized Advanced Male 461.8 499.1392
#> 5 Below Customized Basic Female 3284.8 3324.5956
#> 6 At Customized Basic Female 2995.0 2933.0787
#> 7 At Customized Proficient Female 1788.8 1783.9704
#> 8 At Customized Advanced Female 360.4 378.8444
#> Percent StandardError
#> 1 38.330025 1.2149501
#> 2 33.357798 0.9636501
#> 3 22.448213 0.7257305
#> 4 5.863965 0.5081607
#> 5 39.482215 1.1460243
#> 6 34.832640 0.7304983
#> 7 21.186066 0.8148916
#> 8 4.499079 0.3888590
aLev1$discrete
#> composite_Level dsex N wtdN Percent
#> 1 Below Basic Male 2880.8 2865.6455 33.666050
#> 2 At Basic Male 3266.2 3236.4034 38.021772
#> 3 At Proficient Male 1877.2 1910.7861 22.448213
#> 4 At Advanced Male 461.8 499.1392 5.863965
#> 5 Below Basic Female 2850.4 2913.8597 34.604399
#> 6 At Basic Female 3429.4 3343.8146 39.710456
#> 7 At Proficient Female 1788.8 1783.9704 21.186066
#> 8 At Advanced Female 360.4 378.8444 4.499079
#> StandardError
#> 1 1.0951825
#> 2 0.9537470
#> 3 0.7257305
#> 4 0.5081607
#> 5 1.1154848
#> 6 0.8650729
#> 7 0.8148916
#> 8 0.3888590
7.2 Calculating Percentiles With percentile
The percentile function compares a numeric vector of percentiles in the range 0 to 100 for a data year. For example, to compare the NAEP Primer’s subject composite scale at the 10th, 25th, 50th, 75th, and 90th percentiles, include these as integers in the percentiles argument:
pct1 <- percentile(variable = "composite", percentiles = c(10, 25, 50, 75, 90), data = sdf)
pct1
#> Percentile
#> Call: percentile(variable = "composite", percentiles = c(10, 25, 50,
#> 75, 90), data = sdf)
#> full data n: 17606
#> n used: 16915
#>
#> percentile estimate se df confInt.ci_lower
#> 10 227.7226 1.0585355 39.78256 225.2284
#> 25 251.9626 1.0179363 42.53475 249.7120
#> 50 277.4784 1.1375443 51.15378 275.7035
#> 75 301.1827 0.9141083 70.56403 299.4265
#> 90 321.9303 0.9061950 62.07559 319.9351
#> confInt.ci_upper
#> 230.0172
#> 254.0142
#> 279.1926
#> 302.8973
#> 324.0329
7.3 Correlating Variables With cor.sdf
EdSurvey features multiple correlation methods for data exploration and analysis that fully account for the complex sample design in NCES data by using the cor.sdf function. These features include the following correlation procedures:
- Pearson product-moment correlations for continuous variables
- Spearman rank correlation for ranked variables
- polyserial correlations for one categorical and one continuous variable
- polychoric correlations for two categorical variables
- correlations among plausible values of the subject scales and subscales (marginal correlation coefficients, which uses the Pearson type)
7.3.1 Weighted Correlations
In the following example, b013801, t088001, and the full sample weight origwt are read in to calculate the correlation using the Pearson method. Similar to other EdSurvey functions, the data are removed automatically from memory after the correlation is run.
cor_pearson <- cor.sdf(x = "b013801", y = "t088001", data = sdf,
method = "Pearson", weightVar = "origwt")
#> Converting "b013801" to a continuous variable.
#> Converting "t088001" to a continuous variable.It is important to note the order of levels to ensure that the correlations are functioning as intended. Printing a correlation object will provide a condensed summary of the correlation details and the order of levels for each variable:
cor_pearson
#> Method: Pearson
#> full data n: 17606
#> n used: 14492
#>
#> Correlation: -0.07269657
#> Standard Error: 0.02022161
#> Confidence Interval: [-0.1134367, -0.03171236]
#>
#> Correlation Levels:
#> Levels for Variable 'b013801' (Lowest level first):
#> 1. 0-10
#> 2. 11-25
#> 3. 26-100
#> 4. >100
#> Levels for Variable 't088001' (Lowest level first):
#> 1. Less than 3 hours
#> 2. 3-4.9 hours
#> 3. 5-6.9 hours
#> 4. 7 hours or moreVariables in cor.sdf can be recoded and reordered. Variable levels and values can be redefined given the desired specifications. For example, b017451 and t088001 are correlated using the Pearson method, with the levels "2 or 3 times a week" and "Every day" of the variable b017451 being recoded to "Frequently" within a list of lists in the recode argument:
cor_recode <- cor.sdf(x = "b017451", y = "t088001", data = sdf,
method = "Pearson", weightVar = "origwt",
recode = list(b017451 = list(from = c("2 or 3 times a week", "Every day"),
to = c("Frequently"))))
#> Converting "b017451" to a continuous variable.
#> Converting "t088001" to a continuous variable.
cor_recode
#> Method: Pearson
#> full data n: 17606
#> n used: 14468
#>
#> Correlation: -0.01949923
#> Standard Error: 0.01198974
#> Confidence Interval: [-0.04386941, 0.004894141]
#>
#> Correlation Levels:
#> Levels for Variable 'b017451' (Lowest level first):
#> 1. Never or hardly ever
#> 2. Once every few weeks
#> 3. About once a week
#> 4. Frequently
#> Levels for Variable 't088001' (Lowest level first):
#> 1. Less than 3 hours
#> 2. 3-4.9 hours
#> 3. 5-6.9 hours
#> 4. 7 hours or moreRecoding is useful when a level is very thinly populated (so it might merit combination with another level) or when changing the value label to something more appropriate for a particular analysis.
The variables b017451 and t088001 are correlated using the Pearson method in the following example, with t088001’s values of "Less than 3 hours", "3-4.9 hours", "5-6.9 hours", and "7 hours or more" being reordered to "7 hours or more", "5-6.9 hours", "3-4.9 hours", and "Less than 3 hours" with the "7 hours or more" as the lowest level of the list:
cor_reorder <- cor.sdf(x = "b017451", y = "t088001", data = sdf,
method = "Pearson", weightVar = "origwt",
reorder = list(t088001 = c("7 hours or more", "5-6.9 hours",
"3-4.9 hours", "Less than 3 hours")))
#> Converting "b017451" to a continuous variable.
#> Converting "t088001" to a continuous variable.
cor_reorder
#> Method: Pearson
#> full data n: 17606
#> n used: 14468
#>
#> Correlation: 0.02048827
#> Standard Error: 0.01241005
#> Confidence Interval: [-0.004827359, 0.04577766]
#>
#> Correlation Levels:
#> Levels for Variable 'b017451' (Lowest level first):
#> 1. Never or hardly ever
#> 2. Once every few weeks
#> 3. About once a week
#> 4. 2 or 3 times a week
#> 5. Every day
#> Levels for Variable 't088001' (Lowest level first):
#> 1. 7 hours or more
#> 2. 5-6.9 hours
#> 3. 3-4.9 hours
#> 4. Less than 3 hoursChanging the order of the levels might be useful to modify a variable that is out of order or when reversing the orientation of a series. The reorder argument also is suitable when implemented in conjunction with recoded levels.
NOTE: As an alternative, recoding can be completed within getData. To see additional examples of recoding and reordering, use ?cor.sdf in the R console.
The marginal correlation coefficient among plausible values of the subject scales and subscales can be calculated using the cor.sdf function and the Pearson method. The subject subscales num_oper and algebra are correlated in this example:
cor3_mcc <- cor.sdf(x = "num_oper", y = "algebra", data = sdf, method = "Pearson")
cor3_mcc
#> Method: Pearson
#> full data n: 17606
#> n used: 16915
#>
#> Correlation: 0.8924728
#> Standard Error: 0.004867251
#> Confidence Interval: [0.8822278, 0.901873]Use the showPlausibleValues function to return the plausible values of an edsurvey.data.frame to calculate the correlation coefficients between subject scales or subscales.
The cor.sdf function features multiple methods for data exploration and analysis using correlations. The following example shows the differences in correlation coefficients among the Pearson, Spearman, and polychoric methods using a subset of the edsurvey.data.frame data, in which dsex == 1 (saved as the sdf_dnf object), b017451, pared, and the full sample weight origwt:
sdf_dnf <- subset(x = sdf, subset = dsex == 1)
cor_pearson <- cor.sdf(x = "b017451", y = "pared", data = sdf_dnf,
method = "Pearson", weightVar = "origwt")
#> Converting "b017451" to a continuous variable.
#> Converting "pared" to a continuous variable.
cor_spearman <- cor.sdf(x = "b017451", y = "pared", data = sdf_dnf,
method = "Spearman", weightVar = "origwt")
cor_polychoric <- cor.sdf(x = "b017451", y = "pared", data = sdf_dnf,
method = "Polychoric", weightVar = "origwt")
cbind(Correlation = c(Pearson = cor_pearson$correlation,
Spearman = cor_spearman$correlation,
Polychoric = cor_polychoric$correlation))
#> Correlation
#> Pearson 0.08027069
#> Spearman 0.06655368
#> Polychoric 0.06972564Plausible values for subject scales and subscales also can be correlated with variables using the cor.sdf function. In this case, the five plausible values for composite, b017451, and the full sample weight origwt are read in to calculate the correlation coefficients using the Pearson, Spearman, and polyserial methods:
cor_pearson2 <- cor.sdf(x = "composite", y = "b017451", data = sdf_dnf,
method = "Pearson", weightVar = "origwt")
#> Converting "b017451" to a continuous variable.
cor_spearman2 <- cor.sdf(x = "composite", y = "b017451", data = sdf_dnf,
method = "Spearman", weightVar = "origwt")
cor_polyserial2 <- cor.sdf(x = "composite", y = "b017451", data = sdf_dnf,
method = "Polyserial", weightVar = "origwt")7.3.2 Unweighted Correlations
The cor.sdf function also features the ability to perform correlations without accounting for weights. The cor.sdf function automatically accounts for the default sample weights of the NCES dataset read for analysis in weightVar = "default" but can be modified by setting weightVar = NULL. The following example shows the correlation coefficients of the Pearson and Spearman methods of the variables pared and b017451 while excluding weights:
cor_pearson_unweighted <- cor.sdf(x = "b017451", y = "pared", data = sdf,
method = "Pearson", weightVar = NULL)
#> Converting "b017451" to a continuous variable.
#> Converting "pared" to a continuous variable.
cor_pearson_unweighted
#> Method: Pearson
#> full data n: 17606
#> n used: 16278
#>
#> Correlation: 0.05316366
#> Standard Error: NA
#> Confidence Interval: [NA]
#>
#> Correlation Levels:
#> Levels for Variable 'b017451' (Lowest level first):
#> 1. Never or hardly ever
#> 2. Once every few weeks
#> 3. About once a week
#> 4. 2 or 3 times a week
#> 5. Every day
#> Levels for Variable 'pared' (Lowest level first):
#> 1. Did not finish H.S.
#> 2. Graduated H.S.
#> 3. Some ed after H.S.
#> 4. Graduated college
#> 5. I Don't Know
cor_spearman_unweighted <- cor.sdf(x = "b017451", y = "pared", data = sdf,
method = "Spearman", weightVar = NULL)
cor_spearman_unweighted
#> Method: Spearman
#> full data n: 17606
#> n used: 16278
#>
#> Correlation: 0.04283483
#> Standard Error: NA
#> Confidence Interval: [NA]
#>
#> Correlation Levels:
#> Levels for Variable 'b017451' (Lowest level first):
#> 1. Never or hardly ever
#> 2. Once every few weeks
#> 3. About once a week
#> 4. 2 or 3 times a week
#> 5. Every day
#> Levels for Variable 'pared' (Lowest level first):
#> 1. Did not finish H.S.
#> 2. Graduated H.S.
#> 3. Some ed after H.S.
#> 4. Graduated college
#> 5. I Don't Know
7.4 Preparing an edsurvey.data.frame.list for Cross Datasets Comparisons
Previous examples demonstrated analyses using one dataset, but most EdSurvey functions—including summary2, achievementLevels, and percentile—support the analysis of multiple datasets at one time through an edsurvey.data.frame.list. The edsurvey.data.frame.list appends edsurvey.data.frame objects into one list, which is useful for looking at data, for example, across time or geographically, and reduces repetition in function calls. For instance, four NAEP mathematics assessments from different years can be combined into an edsurvey.data.frame.list to make a single call to analysis functions for ease of use in comparing, formatting, and/or plotting output data. Data from various countries in an international study can be integrated into an edsurvey.data.frame.list for further analysis.
To prepare an edsurvey.data.frame.list for cross datasets analysis, it is necessary to ensure that variable information is consistent across each edsurvey.data.frame. When comparing groups across data years, it is not uncommon for variable names and labels to change. For example, some data years feature a split-sample design based on accommodations status, thereby containing differences in frequently used demographic variables between samples as well as across data years. Two useful functions in determining these inconsistencies are searchSDF() and levelsSDF(), which return variable names, labels, and levels based on a character string.
7.4.1 Combining Several edsurvey.data.frame Objects Into a Single Object
After standardizing variables between each edsurvey.data.frame, they are combined into an edsurvey.data.frame.list and are ready for analysis. In the following example, sdf is subset into four datasets, appended into an edsurvey.data.frame.list, and assigned unique labels:
# make four subsets of sdf by a location variable-scrpsu, "Scrambled PSU and school code"
sdfA <- subset(x = sdf, subset = scrpsu %in% c(5, 45, 56))
sdfB <- subset(x = sdf, subset = scrpsu %in% c(75, 76, 78))
sdfC <- subset(x = sdf, subset = scrpsu %in% 100:200)
sdfD <- subset(x = sdf, subset = scrpsu %in% 201:300)
#combine four datasets to an `edsurvey.data.frame.list`
sdfl <- edsurvey.data.frame.list(datalist = list(sdfA, sdfB, sdfC, sdfD),
labels = c("A locations","B locations",
"C locations","D locations"))This edsurvey.data.frame.list can now be analyzed in other EdSurvey functions.
7.4.2 Recommended Workflow for Standardizing Variables in Cross Datasets Comparisons
Although EdSurvey features several methods to resolve inconsistencies across edsurvey.data.frames, the following approach is recommended:
- Connect to each dataset using a read function, such as
readNAEP(). - Recode each discrepant variable name and level using
recode.sdf()andrename.sdf(). - Combine datasets into one
edsurvey.data.frame.listobject. - Analyze datasets using the
edsurvey.data.frame.listobject.
NOTE: It also is possible to retrieve and recode variables with the getData function; further details and examples of this method appear in the vignette titled Using the getData Function in EdSurvey.
7.5 Estimating the Difference in Two Statistics With gap
Gap analysis is a term often used in NAEP that refers to a methodology that estimates the difference between two statistics (e.g., mean scores, achievement level percentages, percentiles, and student group percentages) for two groups in a population. A gap occurs when one group outperforms the other group, such that the difference between the two statistics is statistically significant (i.e., the difference is larger than the margin of error).
The gap analysis can be comparisons
- between groups (e.g., male students versus female students) by or across years,
- of the same group between years (e.g., male students in 2017 versus in 2019), or
- between jurisdictions (e.g., two states, district versus home state, state versus national public) by or across years.
Independent tests with an alpha level of .05 are performed for most of these types of comparisons. For comparisons between jurisdictions, a dependent test is used for the case in which one jurisdiction is contained in another (e.g., state versus national public).
It is typical to test two statistics (e.g., two groups or 2 years) at a time; if you want to test more than that, multiple comparison procedures should be applied for more conservative results. For more information on gap analysis and multiple comparison, see Drawing Inferences From NAEP Results.
7.5.1 Performing Gap Analysis and Understanding the Summary Output
The following example demonstrates the gap function, comparing the gender difference in achievement:
mathGap <- gap(variable = "composite", data = sdf,
groupA = dsex == "Male", groupB = dsex == "Female")
mathGap
#> Call: gap(variable = "composite", data = sdf, groupA = dsex == "Male",
#> groupB = dsex == "Female")
#>
#> Labels:
#> group definition nFullData nUsed
#> A dsex == "Male" 17606 8486
#> B dsex == "Female" 17606 8429
#>
#> Percentage:
#> pctA pctAse pctB pctBse diffAB covAB
#> 50.27015 0.5016796 49.72985 0.5016796 0.5402935 -0.2516824
#> diffABse diffABpValue dofAB
#> 1.003359 0.5924778 53.45667
#>
#> Results:
#> estimateA estimateAse estimateB estimateBse diffAB
#> 276.7235 0.8207151 275.0458 0.9402535 1.677756
#> covAB diffABse diffABpValue dofAB
#> 0.5676583 0.6498719 0.01259479 53.70969The gap output contains three blocks: labels, percentage, and results.
- The first block, labels, shows the definition of groups A and B, along with a reminder of the full data n count (
nFullData) and the n count of the number of individuals who are in the two subgroups with valid scores (nUsed). - The second block, percentage, shows the percentage of individuals who fall into each category, with omitted levels removed.
- The third block, results, shows the estimated outcomes from the two groups listed in the columns
estimateAandestimateB. ThediffABcolumn shows the estimated difference between the two groups, and thediffABsecolumn shows the standard error of the difference. t-test significance results show indifABpValue, with the degrees of freedom following. When sampling survey respondents through cluster sampling designs (e.g., a design involving sampling students from the same classrooms or schools), these respondents have more in common than randomly selected individuals. Therefore,EdSurveycalculates a covariance between groups from the same assessment sample (same assessment and year), which appears in thecovABcolumn. Even when selecting respondents through simple random sampling, little harm occurs in estimating the covariance because it will be close to zero.
Users can choose to return only the data.frame detailing the results using
mathGap$results
#> estimateA estimateAse estimateB estimateBse diffAB
#> 1 276.7235 0.8207151 275.0458 0.9402535 1.677756
#> covAB diffABse diffABpValue dofAB
#> 1 0.5676583 0.6498719 0.01259479 53.709697.5.2 Gap Analysis Across Years
For illustration purposes, we first generate two fake datasets for Year 1 and Year 2 to use in examples. You can skip this step if you already have cross-year datasets handy.
set.seed(42)
year1 <- EdSurvey:::copyDataToTemp(f0 = "M32NT2PM")
year2 <- EdSurvey:::copyDataToTemp(f0 = "M40NT2PM")The following example demonstrates the gap function, comparing the gender gap between year1 and year2 datasets, which are appended into an edsurvey.data.frame.list:
# combine two datasets
mathList <- edsurvey.data.frame.list(datalist = list(year1, year2),
labels = c("math year1", "math year2"))
# perform cross year analysis between gender
mathGap2 <- gap(variable = "composite", data = mathList,
groupA = dsex == "Male", groupB = dsex == "Female")Each gap output contains a data.frame detailing the results of the analyses, which are returned using the following:
mathGap2$results
#> labels estimateA estimateAse estimateB estimateBse
#> 1 math year1 277.2735 1.014495 274.9149 1.040229
#> 2 math year2 276.8393 1.056766 274.3754 1.114861
#> diffAB covAB diffABse diffABpValue dofAB
#> 1 2.358576 0.3694072 1.1715210 0.05398869 27.44776
#> 2 2.463876 0.7071580 0.9722933 0.01338217 74.24251
#> diffAA covAA diffAAse diffAApValue dofAA diffBB
#> 1 NA NA NA NA NA NA
#> 2 0.4342073 0 1.464908 0.7678634 65.12246 0.5395077
#> covBB diffBBse diffBBpValue dofBB diffABAB covABAB
#> 1 NA NA NA NA NA NA
#> 2 0 1.524792 0.7241024 117.9997 -0.1053004 0
#> diffABABse diffABABpValue dofABAB sameSurvey
#> 1 NA NA NA NA
#> 2 1.522437 0.945065 66.60037 FALSEWhen the data argument is an edsurvey.data.frame.list, the summary results include the following information:
- the group means (
estimateA/estimateB) and standard errors (estimateAse/estimateBse) across a variable (typically data years) - the difference between the values of
estimateAandestimateB, as well as its respective standard errors and p-value (each starting withdiffAB) - the difference between the values of
estimateAacross a variable compared with the reference dataset, as well as its respective standard errors and p-value (each starting withdiffAA) - the difference within the values of
estimateBacross a variable compared with the reference dataset, as well as its respective standard errors and p-value (each starting withdiffBB) - the difference between the difference of
estimateAandestimateBacross a variable compared with the reference dataset, as well as its respective standard errors and p-value (each starting withdiffABAB) - the value
sameSurvey, which indicates if a line in the data output uses the same survey as the reference line (a logical:TRUE/FALSE)
For example, in mathGap2$results,
- The gap in mean mathematics scores between the
dsexvariables in Year 1 (diffAB) is2.358576. - The gap in mean mathematics scores within the
dsexvariables across data years wheregroupA = "Male"(diffAA) is0.4342073. - The gap in mean mathematics scores within the
dsexvariables across data years wheregroupB = "Female"(diffBB) is0.5395077. - The gap in mean mathematics scores between the
dsexvariables across data years (diffABAB) is-0.1053004.
In addition to the summary results, the gap output also contains a data.frame of percentage gaps, in a format matching the data.frame of the previous results. This is returned by using the following:
mathGap2$percentage
#> labels pctA pctAse pctB pctBse
#> 1 math year1 50.31267 0.7732424 49.68733 0.7732424
#> 2 math year2 51.04887 0.7316137 48.95113 0.7316137
#> diffAB covAB diffABse diffABpValue dofAB
#> 1 0.6253492 -0.5979038 1.546485 0.6884604 34.19288
#> 2 2.0977415 -0.5352586 1.463227 0.1569309 59.25477
#> diffAA covAA diffAAse diffAApValue dofAA diffBB
#> 1 NA NA NA NA NA NA
#> 2 -0.7361961 0 1.064501 0.4911036 83.97934 0.7361961
#> covBB diffBBse diffBBpValue dofBB diffABAB covABAB
#> 1 NA NA NA NA NA NA
#> 2 0 1.064501 0.4911036 83.97934 -1.472392 0
#> diffABABse diffABABpValue dofABAB
#> 1 NA NA NA
#> 2 2.129002 0.4911036 83.979347.5.3 Gap Analysis of Jurisdictions
Comparisons of district, state, and national jurisdictions also can be performed using the gap function. The next example demonstrates how to compare multiple datasets, each from a jurisdiction, using the edsurvey.data.frame.list object sdfl, created previously and representing data from four locations.
mathlocGap <- gap(variable = "composite", data = sdfl,
groupA = dsex == "Male", groupB = dsex == "Female")
mathlocGap$results
#> labels estimateA estimateAse estimateB estimateBse
#> 1 A locations 294.9192 6.158446 278.4914 4.998736
#> 2 B locations 290.7389 19.347898 296.2575 18.361466
#> 3 C locations 286.5300 3.707036 294.3619 3.838862
#> 4 D locations 285.8196 37.473667 279.3090 17.786705
#> diffAB covAB diffABse diffABpValue dofAB
#> 1 16.427856 26.692493 3.086880 0.001331239 6.590889
#> 2 -5.518624 340.429882 5.533971 0.353403676 6.678675
#> 3 -7.831865 3.802534 4.568798 0.134082911 6.418453
#> 4 6.510538 653.985648 20.314313 0.767500316 3.362254
#> diffAA covAA diffAAse diffAApValue dofAA
#> 1 NA NA NA NA NA
#> 2 4.180366 84.7127213 15.583394 0.8012387 4.174503
#> 3 8.389230 0.5497927 7.111187 0.2760963 7.105454
#> 4 9.099644 -0.6240987 37.992768 0.8244191 3.404922
#> diffBB covBB diffBBse diffBBpValue dofBB
#> 1 NA NA NA NA NA
#> 2 -17.7661140 59.0011184 15.624614 0.30822190 4.882245
#> 3 -15.8704905 -0.2746742 6.346146 0.02943236 11.018163
#> 4 -0.8176736 -0.2150138 18.487408 0.96692113 3.848665
#> diffABAB covABAB diffABABse diffABABpValue dofABAB
#> 1 NA NA NA NA NA
#> 2 21.946480 -5.1831666 7.107742 0.018774175 6.658063
#> 3 24.259720 -0.2137924 5.552506 0.001956103 8.690019
#> 4 9.917317 -2.5253958 20.670049 0.660489851 3.410698
#> sameSurvey
#> 1 NA
#> 2 TRUE
#> 3 TRUE
#> 4 TRUEIn NAEP, the jurisdiction information is included in a single restricted-use data file. The following examples illustrate, using NAEP, how to conduct comparisons between (a) states, (b) a state versus the nation, and (c) a district versus the home state.
# comparisons of two states
mathStateGap <- gap(variable = "composite", data = mathList,
fips == "California", fips == "Virginia")
# comparisons of state to all public schools in nation
mathList <- subset(mathList, schtyp2 == "Public")
mathStateNationGap <- gap(variable = "composite", data = mathList,
fips == "California", schtyp2 == "Public")
# comparisons of district to state
mathStateDistrictGap <- gap("composite", data = mathList,
distcod == "Los Angeles", fips == "California")7.5.4 Gap Analysis of Achievement Levels and Percentiles
Gap analysis also may be performed across achievement levels and percentiles by specifying the values in the achievementLevel or percentiles arguments, respectively. Using our previous edsurvey.data.frame.list object (mathList), setting achievementLevel=c("Basic", "Proficient", "Advanced") will perform comparisons between groups by and across years for each achievement level value.
mathALGap <- gap(variable = "composite", data = mathList,
groupA = dsex == "Male", groupB = dsex == "Female",
achievementLevel = c("Basic", "Proficient", "Advanced"))
mathALGap$results
#> achievementLevel labels estimateA estimateAse
#> 1 At or Above Basic math year1 66.870662 1.2335219
#> 2 At or Above Basic math year2 66.008354 1.4761274
#> 3 At or Above Proficient math year1 28.719053 1.2778962
#> 4 At or Above Proficient math year2 28.469990 1.0605786
#> 5 At Advanced math year1 6.111211 0.6868165
#> 6 At Advanced math year2 5.833023 0.7136854
#> estimateB estimateBse diffAB covAB diffABse
#> 1 65.100350 1.3290706 1.770311 0.47346693 1.5300559
#> 2 64.212592 1.2702205 1.795762 0.80498819 1.4773070
#> 3 25.546317 1.1150117 3.172735 0.16683642 1.5945522
#> 4 25.852175 1.2256185 2.617815 0.63726122 1.1629469
#> 5 4.509459 0.5578078 1.601751 0.09886164 0.7649465
#> 6 4.353453 0.4823550 1.479570 0.11276154 0.7186725
#> diffABpValue dofAB diffAA covAA diffAAse
#> 1 0.25305547 47.43947 NA NA NA
#> 2 0.22899798 58.93240 0.8623073 0 1.9236757
#> 3 0.05430082 35.80025 NA NA NA
#> 4 0.02759747 68.48216 0.2490623 0 1.6606763
#> 5 0.04228707 42.36482 NA NA NA
#> 6 0.04512671 46.64694 0.2781884 0 0.9904867
#> diffAApValue dofAA diffBB covBB diffBBse
#> 1 NA NA NA NA NA
#> 2 0.6559148 49.66853 0.8877581 0 1.8384474
#> 3 NA NA NA NA NA
#> 4 0.8810447 115.55769 -0.3058583 0 1.6569224
#> 5 NA NA NA NA NA
#> 6 0.7795513 79.05949 0.1560067 0 0.7374387
#> diffBBpValue dofBB diffABAB covABAB diffABABse
#> 1 NA NA NA NA NA
#> 2 0.6302057 102.66886 -0.02545076 0 2.126854
#> 3 NA NA NA NA NA
#> 4 0.8538879 109.77788 0.55492055 0 1.973586
#> 5 NA NA NA NA NA
#> 6 0.8331024 66.60928 0.12218164 0 1.049587
#> diffABABpValue dofABAB sameSurvey
#> 1 NA NA NA
#> 2 0.9904753 104.21223 FALSE
#> 3 NA NA NA
#> 4 0.7793705 73.18939 FALSE
#> 5 NA NA NA
#> 6 0.9075937 87.93697 FALSESimilarly, setting percentiles = c(10, 25, 50, 75, 90) will perform comparisons between groups by and across years for each percentile value.
mathPercentilesGap <- gap(variable = "composite", data = mathList,
groupA = dsex == "Male", groupB = dsex == "Female",
percentiles = c(10, 25, 50, 75, 90))
mathPercentilesGap$results
#> percentiles labels estimateA estimateAse estimateB
#> 1 10 math year1 228.5492 0.9667854 227.0247
#> 2 10 math year2 227.9186 2.4995864 226.2819
#> 3 25 math year1 253.0893 0.9471983 250.9874
#> 4 25 math year2 252.2491 1.3755823 250.0428
#> 5 50 math year1 278.2843 1.3730106 276.9812
#> 6 50 math year2 278.0656 1.6903894 276.3454
#> 7 75 math year1 302.8779 1.3682276 299.6181
#> 8 75 math year2 302.7776 0.8726368 299.9592
#> 9 90 math year1 324.2191 1.7859545 320.1731
#> 10 90 math year2 324.3229 1.8148749 319.6371
#> estimateBse diffAB covAB diffABse diffABpValue
#> 1 2.2177507 1.524483 0.12874954 2.365501 0.524380292
#> 2 2.2006815 1.636691 1.59047562 2.812469 0.567514040
#> 3 1.5062090 2.101920 0.06906226 1.740036 0.231540228
#> 4 1.3677150 2.206282 0.05717917 1.910108 0.253858464
#> 5 0.9264616 1.303117 0.14110321 1.568848 0.411462617
#> 6 1.3722702 1.720201 1.27774827 1.478190 0.250443398
#> 7 1.1878050 3.259775 0.07671289 1.769040 0.073719644
#> 8 1.0668784 2.818378 0.39727222 1.051275 0.009435823
#> 9 1.2427261 4.046013 0.13587502 2.112404 0.075499842
#> 10 1.3593064 4.685793 0.47512103 2.047252 0.026239504
#> dofAB diffAA covAA diffAAse diffAApValue dofAA
#> 1 28.76492 NA NA NA NA NA
#> 2 18.81623 0.6305664 0 2.680038 0.8155427 30.88172
#> 3 63.44991 NA NA NA NA NA
#> 4 47.38973 0.8401989 0 1.670153 0.6168345 57.62887
#> 5 37.37699 NA NA NA NA NA
#> 6 46.73963 0.2186734 0 2.177745 0.9203339 63.31403
#> 7 35.58427 NA NA NA NA NA
#> 8 60.84149 0.1002895 0 1.622819 0.9508935 72.08366
#> 9 14.41527 NA NA NA NA NA
#> 10 51.30331 -0.1038355 0 2.546253 0.9676270 52.23293
#> diffBB covBB diffBBse diffBBpValue dofBB
#> 1 NA NA NA NA NA
#> 2 0.7427746 0 3.124327 0.8129968 53.19276
#> 3 NA NA NA NA NA
#> 4 0.9445612 0 2.034529 0.6434062 106.40957
#> 5 NA NA NA NA NA
#> 6 0.6357575 0 1.655735 0.7024377 56.57640
#> 7 NA NA NA NA NA
#> 8 -0.3411076 0 1.596593 0.8316963 49.70196
#> 9 NA NA NA NA NA
#> 10 0.5359443 0 1.841761 0.7717175 90.91000
#> diffABAB covABAB diffABABse diffABABpValue dofABAB
#> 1 NA NA NA NA NA
#> 2 -0.1122082 0 3.674993 0.9757890 41.32595
#> 3 NA NA NA NA NA
#> 4 -0.1043623 0 2.583842 0.9678588 104.78313
#> 5 NA NA NA NA NA
#> 6 -0.4170841 0 2.155534 0.8470519 81.70437
#> 7 NA NA NA NA NA
#> 8 0.4413971 0 2.057834 0.8308790 60.72581
#> 9 NA NA NA NA NA
#> 10 -0.6397798 0 2.941682 0.8288465 43.44324
#> sameSurvey
#> 1 NA
#> 2 FALSE
#> 3 NA
#> 4 FALSE
#> 5 NA
#> 6 FALSE
#> 7 NA
#> 8 FALSE
#> 9 NA
#> 10 FALSE7.5.5 Multiple Comparisons
When making groups or families of comparisons in a single analysis, such as comparing White students with minority student groups in terms of test scores, the probability of finding significance by chance for at least one comparison increases with the family size or the number of comparisons. Multiple methods exist to adjust p-values to hold the significance level for a set of comparisons at a particular level (e.g., 0.05), and such adjustments are called multiple comparison procedures. NAEP employs two procedures: the Benjamini-Hochberg false discovery rate (FDR) procedure (Benjamini & Hochberg, 1995) and the Bonferroni procedure. The Bonferroni procedure was used prior to the 1996 assessment. Thereafter, NAEP has used the FDR procedure. A detailed explanation of the NAEP multiple comparison procedures can be found at Comparison of Multiple Groups.
Typically, the number of comparisons is determined as the number of possible statistical tests in a single analysis. However, in NAEP reports, when comparing multiple years and multiple jurisdictions (e.g., multiple states versus the United States as a whole), usually neither the number of years nor the number of jurisdictions counts toward the number of comparisons.
The next example illustrates how to adjust the p-values using the Bonferroni and FDR procedures through R’s p.adjust function. First, generate the gaps comparing the achievement differences ("composite") between one race/ethnicity group (in this case 'White') and the other five levels of sdracem.
levelResults1 <- gap(variable = "composite", data = sdf, groupA = sdracem == "White",
groupB = sdracem == "Black")
levelResults2 <- gap(variable = "composite", data = sdf, groupA = sdracem == "White",
groupB = sdracem == "Hispanic")
levelResults3 <- gap(variable = "composite", data = sdf, groupA = sdracem == "White",
groupB = sdracem == "Asian/Pacific Island")
levelResults4 <- gap(variable = "composite", data = sdf, groupA = sdracem == "White",
groupB = sdracem == "Amer Ind/Alaska Natv")
levelResults5 <- gap(variable = "composite", data = sdf, groupA = sdracem == "White",
groupB = sdracem == "Other")We’ll append these results to a list and use a for-loop to retrieve the results data.frame from each gap object (levelResults1 through levelResults5). For clarity, we’ll also create two new variables showing the comparison levels.
resultsList <- list(levelResults1, levelResults2, levelResults3, levelResults4, levelResults5)
fullResults <- data.frame()
for(i in 1:length(resultsList)) {
fullResults <- rbind(fullResults, resultsList[[i]]$results)
}
fullResults$levelA <- c("White")
fullResults$levelB <- c("Black", "Hispanic", "Asian/Pacific Island", "Amer Ind/Alaska Natv", "Other")
fullResults
#> estimateA estimateAse estimateB estimateBse diffAB
#> 1 287.301 0.7991882 253.4925 1.349386 33.808504
#> 2 287.301 0.7991882 259.8218 1.258471 27.479214
#> 3 287.301 0.7991882 289.8092 3.290948 -2.508196
#> 4 287.301 0.7991882 265.4023 3.630704 21.898677
#> 5 287.301 0.7991882 281.3191 5.154681 5.981855
#> covAB diffABse diffABpValue dofAB levelA
#> 1 0.23565724 1.410046 0.000000e+00 40.83522 White
#> 2 0.10045282 1.421811 0.000000e+00 27.01301 White
#> 3 0.57184616 3.213308 4.473733e-01 14.78845 White
#> 4 -0.02820715 3.725201 6.830990e-06 21.70421 White
#> 5 -0.05243699 5.226310 2.615158e-01 29.74570 White
#> levelB
#> 1 Black
#> 2 Hispanic
#> 3 Asian/Pacific Island
#> 4 Amer Ind/Alaska Natv
#> 5 OtherOnce reshaped, the p-values in each gap result can be adjusted via p.adjust(). The following examples show both the Bonferroni and FDR adjustment methods:
fullResults$diffABpValueBon <- p.adjust(fullResults$diffABpValue, method = "bonferroni")
fullResults$diffABpValueFDR <- p.adjust(fullResults$diffABpValue, method = "BH")
fullResults
#> estimateA estimateAse estimateB estimateBse diffAB
#> 1 287.301 0.7991882 253.4925 1.349386 33.808504
#> 2 287.301 0.7991882 259.8218 1.258471 27.479214
#> 3 287.301 0.7991882 289.8092 3.290948 -2.508196
#> 4 287.301 0.7991882 265.4023 3.630704 21.898677
#> 5 287.301 0.7991882 281.3191 5.154681 5.981855
#> covAB diffABse diffABpValue dofAB levelA
#> 1 0.23565724 1.410046 0.000000e+00 40.83522 White
#> 2 0.10045282 1.421811 0.000000e+00 27.01301 White
#> 3 0.57184616 3.213308 4.473733e-01 14.78845 White
#> 4 -0.02820715 3.725201 6.830990e-06 21.70421 White
#> 5 -0.05243699 5.226310 2.615158e-01 29.74570 White
#> levelB diffABpValueBon diffABpValueFDR
#> 1 Black 0.000000e+00 0.000000e+00
#> 2 Hispanic 0.000000e+00 0.000000e+00
#> 3 Asian/Pacific Island 1.000000e+00 4.473733e-01
#> 4 Amer Ind/Alaska Natv 3.415495e-05 1.138498e-05
#> 5 Other 1.000000e+00 3.268948e-01